Challenge 3 : Core width/height calculation

Hi All,


Challenge to test your Floorplan concepts.

what will be Core height and width as a output of  below command ?

 

initialize_floorplan  -boundary {{0 0}{10 10.01}} -core_offset "0.624 1.014 0.624 1.014"


core area


Please share  your views in comment.

If you need help to revise concept, refer floorplan guide : Mastering Floorplanning: A Comprehensive Step-by-Step Guide"

Comments

  1. Core width = 8.752 units
    Core height = 7.982 units

    ReplyDelete
    Replies
    1. Afroz, Thank you for being first one to share your views here...
      However this is not right answer... Please think what are you missing and try to come up with updated numbers.

      Delete
    2. As per my calculation Core height should be 10.01/0.169 = 59.23 so , height would be 0.169*59(We have to consider integer)= 9.971, but i am not able to get width.

      Delete
    3. Tajes,
      Yes. You are in right direction.
      Just think how did you get 0.169. you will get answer to your question.

      Delete
    4. Core height - 10.01
      Core width - 10

      Delete
  2. Varshith Reddy ChittireddyAugust 9, 2025 at 8:39 PM

    Width - 0
    Height - 0 .!!!

    ReplyDelete
    Replies
    1. Varshith,
      Answer is not 0.
      Could you please explain your views here..how come you arrived with 0 width and height?

      Delete
    2. Varshith,
      Please show your calculation.

      Delete
  3. This comment has been removed by the author.

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  4. This comment has been removed by the author.

    ReplyDelete
  5. Core Width = 9.88 units, Core Height = 8.36 units

    ReplyDelete
    Replies
    1. Thank you Saisrujana for sharing your views...
      Before commenting on your answer, please share your calculations how mentioned width/height numbers are arrived.

      Delete
    2. Site width: 0.152 units
      Site height: 1.672 units

      Calculate how many full sites fit in each direction:

      ⌊10.00 / 0.152⌋ = 65 sites horizontally
      → Actual width = 65 × 0.152 = 9.88 units

      ⌊10.01 / 1.672⌋ = 5 sites vertically
      → Actual height = 5 × 1.672 = 8.36 units


      That makes the answer to be as follows:

      Core Width = 9.88 units, Core Height = 8.36 units

      Delete
    3. Here are the calculations, thanks!

      Delete
    4. Thank you Saisrujana for quick response... (No need comment as anonymous 😀)
      Could you please explain how value of site height and width is arrived?

      Delete
    5. Hi Jignesh, I got the site width and site height directly from the tool using the `report_site` command

      Delete
    6. Appreciate your efforts Saisrujana....
      Fyi.. please note that site height and width is not same for all technology nodes.

      Please refer below 👇 blog to revise Floorplan terminology:
      https://physical-design-asic.blogspot.com/2025/07/floorplan-basics-learn-terms-without.html

      Delete
    7. Got it, thanks for pointing that out and for sharing the blog link - it’s very informative!

      Delete
  6. The core width is the boundary width minus the left and right core offsets:

    Core Width = 10 - 0.624 - 0.624 = 8.752 units

    The core height is the boundary height minus the top and bottom core offsets:

    Core Height = 10.01 - 1.014 - 1.014 = 7.982 units

    ReplyDelete
    Replies
    1. Hi Rithvej,
      Please check the blog post link mentioned at the end of current post.
      It will help to revise Floorplan concepts.
      I am sure you will get correct answer then.

      Delete
    2. Rithvej,
      There is two side core2die so need to update your formula

      Delete

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